Divergence Test |
If the series |
Proof:
Examples 4.2.2:
Suppose the series does converge. Then it must satisfy the
Cauchy criterion. In other words, given any
> 0 there exists
a positive integer N such that whenever
n > m > N
then
|Let m > N and set n = m. Then the series above reduces to| <
![]()
| a n | <if n > N. That, however, is saying that the sequence![]()
converges to zero.